Python Regex

[quest]

I have the following text file:

Output:
S = 0, X are: (1, 0, 1, 1, 0, 0, )S = 0, Z are: (0, 1, 1, 1, 0, 1, )Data bits measurement:0, 0, 0, 1, 1, 1, 1, 0, 0, 1, 0, 0, 0, Measured l0: 1, Measured l1: 0

S = 0, X are: (1, 1, 0, 0, 0, 1, )S = 0, Z are: (1, 1, 0, 0, 1, 1, )Data bits measurement:1, 0, 0, 1, 1, 1, 1, 1, 0, 1, 1, 1, 1, Measured l0: 0, Measured l1: 1

S = 0, X are: (1, 1, 0, 0, 1, 1, )S = 0, Z are: (1, 1, 0, 0, 1, 1, )Data bits measurement:1, 0, 1, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, Measured l0: 1, Measured l1: 0

S = 0, X are: (1, 1, 1, 0, 1, 1, )S = 0, Z are: (0, 0, 0, 1, 0, 0, )Data bits measurement:0, 0, 0, 0, 1, 0, 1, 1, 1, 1, 0, 1, 0, Measured l0: 1, Measured l1: 0

S= 0, X are: (1, 1, 0, 1, 1, 0, )S = 0, Z are: (0, 0, 0, 1, 0, 0, )Data bits measurement:0, 0, 0, 0, 0, 0, 0, 0, 1, 1, 0, 0, 1, Measured l0: 1, Measured l1: 0

S = 0, X are: (1, 1, 0, 0, 1, 1, )S = 0, Z are: (1, 1, 1, 0, 0, 1, )Data bits measurement:1, 0, 1, 1, 1, 1, 1, 1, 0, 1, 1, 0, 1, Measured l0: 1, Measured l1: 0

Now, I want to count how many same Z value I have and I have many l0 I have for this Z value:
For example:

Output:
011101 - 1  and l0 1 (in total)
110011 - 2 and l0 1  (in total)
000100 - 2 and l0 2  (in total)
111001 - 1 and l0 1 (in total)

I thought regex can be nice but I could not manage to use it:
Here is my code:

with open("f.dat") as file:
    lines = file.readlines()
    #Z=re.search("(^Z*)",line)
    for i in re.findall(r'Z are: (=(\d+)&',lines):
           print(i)

And I got this error:

Error:
raise source.error("missing ), unterminated subpattern",
re.error: missing ), unterminated subpattern at position 17