group by property

[bhojendra]

I have a list like:

result = [
  {
    "name: "John",
    "m": "good",
    "n": 1
  },
  {
    "name": 'Alina',
    "m": "good",
    "n": 1
  },
  {
    "name": "Olivia",
    "m": "bad",
    "n": 2
  },
  {
    "name": "Ruby",
    "m": "bad",
    "n": 2
  },
  ...
]

I want to convert it into like this:

result = [
  { // n is 1
    "g": [
      {
        "name": "John",
        "n": 1
      },
      {
        "name":"Alina",
        "n": 1
      }
    ],
    "b": [
      {
        "name": "...",
        "n": 1
      },
      {
        "name": "...",
        "n": 1
      }
    ]
  },
  { // n is 2
    "g": [...],
    "b": [...]
  },
  { // n is 3
   // ...
  }
]

What I'm trying to achieve here is as follows:
- if m is good, g should have group of dictionary where n matches
- if m is bad, b should have group of dictionary where n matches

So, here I have to group them by n and with good and bad property. Hope this is clear.

Please note the value of n is generated with timestamp. I have shown here 1,2,3.. just for ease.