group by property

[bhojendra]

As I said the value of n is generated with timestamp. So it doesn't work. Try the following which results empty list:

List = [
    {
      "name": "John",
      "m": "good",
      "n": 1561895746657
    },
    {
      "name": 'Alina',
      "m": "good",
      "n": 1561895746657
    },
    {
      "name": "Peter",
      "m": "bad",
      "n": 1561895746657
    },
    {
      "name": 'Mary',
      "m": "bad",
      "n": 1561895746657
    },
    {
      "name": "Olivia",
      "m": "bad",
      "n": 1561872416143
    },
    {
      "name": "Ruby",
      "m": "bad",
      "n": 1561872416143
    },
    {
      "name": "Sukuyomi",
      "m": "good",
      "n": 1561872416143
    },
    {
      "name": "Furuhashi",
      "m": "good",
      "n": 1561872416143
    }
  ]
  
  NewList = [{'g' : [], 'b' : []}]
  for Dict in List:
      if Dict['n'] == len(NewList):
          NewList[Dict['n'] - 1][Dict['m'][0]].append(Dict)
      else:
          NewList.append({'g' : [], 'b' : []})
  print(NewList)

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@scidam,

I just tried with standard library. And it works fine. But I'm not sure if I understand them.

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@SheeppOSU,

I would love to use your method coz, I don't need to import other library. So, can you please update your answer once again with the given timestamp?