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Help Understanding Some Code
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Help Understanding Some Code
#1
I'm trying to understand this code:
def readSize(self):
        b1 = ord(self.read(1))
        if b1 & 0b10000000:  # 1 byte
            return b1 & 0b01111111
        elif b1 & 0b01000000:  # 2 bytes
            return unpack(">H", bchr(b1 & 0b00111111) + self.read(1))[0]
        elif b1 & 0b00100000:  # 3 bytes
            return unpack(">L", b"\0" + bchr(b1 & 0b00011111) + self.read(2))[0]
        elif b1 & 0b00010000:  # 4 bytes
            return unpack(">L", bchr(b1 & 0b00001111) + self.read(3))[0]
        elif b1 & 0x00001000:  # 5 bytes
            return unpack(">Q", b"\0\0\0" + bchr(b1 & 0b00000111) + self.read(4))[0]
        elif b1 & 0b00000100:  # 6 bytes
            return unpack(">Q", b"\0\0" + bchr(b1 & 0b0000011) + self.read(5))[0]
        elif b1 & 0b00000010:  # 7 bytes
            return unpack(">Q", b"\0" + bchr(b1 & 0b00000001) + self.read(6))[0]
        elif b1 & 0b00000001:  # 8 bytes
            return unpack(">Q", b"\0" + self.read(7))[0]
        else:
            assert b1 == 0
raise EbmlException("undefined element size")
I've a basic knowledge of bitwise operators via Google. I will get into more depth later. I just don't understand what this code is doing. What is
0b1000000
I know it's a binary number, but what does the "0b" represent? I've seen "0x" prefacing binary numbers (though I don't really get what it means either), but never "0b".
I would appreciate any help decoding this for me.

Thanks,
malonn
Reply


Messages In This Thread
Help Understanding Some Code - by malonn - Jul-21-2018, 03:06 PM
RE: Help Understanding Some Code - by gontajones - Jul-21-2018, 03:13 PM
RE: Help Understanding Some Code - by malonn - Jul-21-2018, 03:28 PM

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