Nov-23-2018, 04:01 AM
Here's how you can build a dictionary on the fly:
# Author: Larz60+ Nov 22, 2018 import os class CreateDict: def __init__(self): os.chdir(os.path.abspath(os.path.dirname(__file__))) def new_dict(self, dictname): setattr(self, dictname, {}) def add_node(self, parent, nodename): node = parent[nodename] = {} return node def add_cell(self, nodename, cellname, value): cell = nodename[cellname] = value return cell def display_dict(self, dictname, level=0): indent = " " * (4 * level) for key, value in dictname.items(): if isinstance(value, dict): print(f'\n{indent}{key}') level += 1 self.display_dict(value, level) else: print(f'{indent}{key}: {value}') if level > 0: level -= 1 def testit(): cd = CreateDict() cd.new_dict('CityList') boston = cd.add_node(cd.CityList, 'Boston') bos_resturants = cd.add_node(boston, 'Resturants') spoke = cd.add_node(bos_resturants, 'Spoke Wine Bar') cd.add_cell(spoke, 'Addr1', '89 Holland St') cd.add_cell(spoke, 'City', 'Sommerville') cd.add_cell(spoke, 'Addr1', '02144') cd.add_cell(spoke, 'Phone', '617-718-9463') highland = cd.add_node(bos_resturants, 'Highland Kitchen') cd.add_cell(highland, 'Addr1', '150 Highland Ave') cd.add_cell(highland, 'City', 'Sommerville') cd.add_cell(highland, 'ZipCode', '02144') cd.add_cell(highland, 'Phone', '617-625-1131') print(f'\nCityList Dictionary') cd.display_dict(cd.CityList) print(f'\nraw data: {cd.CityList}') if __name__ == '__main__': testit()The test routing has the code to reproduce the sample dictionary I show above in post #2
Output:Boston
Resturants
Spoke Wine Bar
Addr1: 02144
City: Sommerville
Phone: 617-718-9463
Highland Kitchen
Addr1: 150 Highland Ave
City: Sommerville
ZipCode: 02144
Phone: 617-625-1131
raw data: {'Boston': {'Resturants': {'Spoke Wine Bar': {'Addr1': '02144', 'City': 'Sommerville', 'Phone': '617-718-9463'}, 'Highland Kitchen': {'Addr1': '150 Highland Ave', 'City': 'Sommerville', 'ZipCode': '02144', 'Phone': '617-625-1131'}}}}