p]Why os.path.exists("abc/d") and os.path.exists("abc/D") treat same

[rajeev1729]

Why os.path.exists("abc/d") and os.path.exists("abc/D") treat same but actually both are different path. Before running create abc folder and then inside abc folder create d folder to test it.

print(os.path.exists("abc/d")==os.path.exists("abc/D"))

Output it gives is true and it should be false.