Find numbers using Regex

[giddyhead]

Instead of finding the whole thing can it be modified to only find the numbers only for example 5one, 5529care, 30over, etc? Thanks

If add a group () to deanhystad code then will get only numbers.

from io import StringIO
import re

test_text = StringIO(
"""25 - not this number1
the cow just over the moon and the sun is in 1the sky
26 - not this number
5one day is soon and soon is near take 5529care, 30over and out
59 - not this number
The covers at near the back of the 59closet, and when found have them place on the each of the beds. However you see the pillow cases use the ones on the 9second shelve."""
)

pattern = re.compile(r"([0-9]+)[a-zA-Z]+|[a-zA-Z]+([0-9]+)")
for line in test_text:
    matches = re.findall(pattern, line)
    if matches:
        print(f"{line}Matches = {matches}\n")
    else:
        print(f"{line}No matches\n") 

Output:
25 - not this number1
Matches = [('', '1')]

the cow just over the moon and the sun is in 1the sky
Matches = [('1', '')]

26 - not this number
No matches

5one day is soon and soon is near take 5529care, 30over and out
Matches = [('5', ''), ('5529', ''), ('30', '')]

59 - not this number
No matches

The covers at near the back of the 59closet, and when found have them place on the each of the beds. However you see the pillow cases use the ones on the 9second shelve.Matches = [('59', ''), ('9', '')]

Clean up.

>>> Matches = [('5', ''), ('5529', ''), ('30', '')]
>>> [i[0] for i in Matches]
['5', '5529', '30']

Got it Thank you!