Hm, let's try:
Now the first try with bytes:
Third try:
Finally you can use this:
Bonus:
Instead of using the list function to construct a list,
use a bytearray. A bytearray is mutable and acts like a list.
There must be a better way.
str.join('', list('Hello World'))
Output:'Hello World'
Success :-)Now the first try with bytes:
bytes.join(b'', list(b'Hello Bytes'))
Error:TypeError: sequence item 0: expected a bytes-like object, str found
This is the problem with the representation. Iterating over bytes returns integers.Third try:
bytearray(list(b'Hello Bytes'))
Output:bytearray(b'Hello Bytes')
This looks better.Finally you can use this:
bytes(bytearray(list(b'Hello Bytes')))
Output:b'Hello Bytes'
But you're right. It's not so easy.Bonus:
Instead of using the list function to construct a list,
use a bytearray. A bytearray is mutable and acts like a list.
bytes(bytearray(b'Hello Bytes'))
Output:b'Hello Bytes'
It's mutable. You can mutate it.ba = bytearray(b'Hello Bytes') ba[0] = b'W'
Error:TypeError: an integer is required
A not so nice solution for it:ba[0] = ord(b'W') ba
Output:bytearray(b'Wello Bytes')
Extending:ba.extend(b' This is the next Chunk') ba
Output:bytearray(b'Wello Bytes This is the next Chunk')
But i know what you mean. Handling with bytes a bit pain in the ass.There must be a better way.
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