How can I get some arguments using argparse?

[Mike Ru]

I am using a module argparse. I need to get arguments and then do something. I can only one argument now, but I cannot get some arguments if an user types two arguments.

1	python demo.py -c work.txt

Now here is my code:

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import sys, argparse   def main():     parser = argparse.ArgumentParser(description="Process some ...")     #parser.add_argument('-n', '--name', required=True, help="name of the user")     parser.add_argument('-n', '--name', required=False, help="name of the user")     parser.add_argument('-a', '--adress', required=False, help="name of the host")     parser.add_argument('-c', '--copy', required=False, help="Copy a file into a server")       args = vars(parser.parse_args())     #if args     for x in args.values():         if x != None:             print(x)   main()

I can get them list_args like that:

1	python demo.py -a Russia -c work.txt

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args = vars(parser.parse_args()) list_args = [] for x in args.values():     if x != None:         list_args.append(x)   print(list_args)

but then I cannot understand where who is.
How to do it?

---

OMG! I resolved it.

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import argparse   def main():     parser = argparse.ArgumentParser(description="Process some ...")       parser.add_argument('-n', '--name', required=False, help="name of the user")     parser.add_argument('-a', '--adress', required=False, help="name of the host")     parser.add_argument('-c', '--copy', required=False, help="Copy a file to the server")       args = vars(parser.parse_args())       if args['name']:         print('i am name {}'.format(args['name']))       if args['adress']:         print('i am adress {}'.format(args['adress']))       if args['copy']:         print('i am copy {}'.format(args['copy']))         main()