Writing the Path to a file properly

[dcw9996]

Hello,

I am 64 years old but new to Python and brand new to this forum. If I due something wrong please let me know.

I purchased a book on python and I'm working through it. I am trying to work on opening/reading/writing to files. I just cannot open a file in another directory from my python script location. I have followed every direction and googled until my fingers are bleeding. I am obviously missing something.

My computer is Windows 10
My python file is saved in Dropbox (I sometimes study from different locations)
Here is my code:

1 2 3 4 5 6 7 8 9 10

import csv import os   path = "This PC/Windows(C:)/Users/dcw99/Documents/Python_basics_work_files/python-basics-exercises-master" \         "/ch11-file-input-and-output/practice_files/"   with open(os.path.join(path, "wonka.csv"), "r") as my_file:     reader = csv.reader(my_file)     for row in reader:         print(row)

I keep getting the error:

Error:
OSerror: [error22] Invalid Argument:"This PC/Windows(C:)/Users/dcw99/Documents/Python_basics_work_files/python-basics-exercises-master" \
		"/ch11-file-input-and-output/practice_files/wonka.csv"

I have typed the path exactly as it appears. I've placed an r immediately in front of the path, as instructed. No joy.

I apologize for asking about something this simple but I am just so frustrated. Any help you can offer would be very appreciated.

Thanks,
Don

[Yoriz]

Try the following as the path

1 2	path = ("C:/Users/dcw99/Documents/Python_basics_work_files/python-basics-exerci"         "ses-master/ch11-file-input-and-output/practice_files/")

[dcw9996]

Yoriz!!

Worked like a charm!!! Thank you so much.