Setting maximum value of Range() in For loop

[pmt]

Hello all, I am trying to use range() and for loop function to change the dictionary keys and values.
Expected output result is to create the keys and values of t{} according to the values in f_set.
The expected result is e.g I would like to create f_set[0]=(e.g 5) and f_set[1]=e.g 2 values and get the t output as {(1, 2, 1): 1, (1, 2, 2): 1, (1, 2, 3): 1, (1, 2, 4): 1, (1, 2, 5): 1,(1, 3, 1): 1, (1, 3, 2): 1}. However, the current output is always taking the maximum value fro m f_set as final value. How can I get the t output as I want to create? Thanks for any help.

1 2 3 4 5 6 7 8 9 10

N=[1,2,3] t={} f_set=[5,2,1,10,15,1,3,1] for x in N:     for y in N:         if x is not y:           for f in f_set:             for f_no in range(1,f+1):               t[x,y,f_no]=1 print(t)

Output:
{(1, 2, 1): 1, (1, 2, 2): 1, (1, 2, 3): 1, (1, 2, 4): 1, (1, 2, 5): 1, (1, 2, 6): 1, (1, 2, 7): 1, (1, 2, 8): 1, (1, 2, 9): 1, (1, 2, 10):
1, (1, 2, 11): 1, (1, 2, 12): 1, (1, 2, 13): 1, (1, 2, 14): 1, (1, 2, 15): 1, (1, 3, 1): 1, (1, 3, 2): 1, (1, 3, 3): 1, (1, 3, 4): 1, (1, 3, 5): 1, (1, 3, 6): 1, (1, 3, 7): 1, (1, 3, 8): 1, (1, 3, 9): 1, (1, 3, 10): 1, (1, 3, 11): 1, (1, 3, 12): 1, (1, 3, 13): 1, (1, 3, 14): 1, (1, 3, 15): 1, (2, 1, 1): 1, (2, 1, 2): 1, (2, 1, 3): 1, (2, 1, 4): 1, (2, 1, 5): 1, (2, 1, 6): 1, (2, 1, 7): 1, (2, 1, 8): 1, (2, 1, 9):
1, (2, 1, 10): 1, (2, 1, 11): 1, (2, 1, 12): 1, (2, 1, 13): 1, (2, 1, 14): 1, (2, 1, 15): 1, (2, 3, 1): 1, (2, 3, 2): 1, (2, 3, 3): 1, (2,
3, 4): 1, (2, 3, 5): 1, (2, 3, 6): 1, (2, 3, 7): 1, (2, 3, 8): 1, (2, 3, 9): 1, (2, 3, 10): 1, (2, 3, 11): 1, (2, 3, 12): 1, (2, 3, 13): 1, (2, 3, 14): 1, (2, 3, 15): 1, (3, 1, 1): 1, (3, 1, 2): 1, (3, 1, 3): 1, (3, 1, 4): 1, (3, 1, 5): 1, (3, 1, 6): 1, (3, 1, 7): 1, (3, 1, 8): 1, (3, 1, 9): 1, (3, 1, 10): 1, (3, 1, 11): 1, (3, 1, 12): 1, (3, 1, 13): 1, (3, 1, 14): 1, (3, 1, 15): 1, (3, 2, 1): 1, (3, 2, 2): 1, (3, 2, 3): 1, (3, 2, 4): 1, (3, 2, 5): 1, (3, 2, 6): 1, (3, 2, 7): 1, (3, 2, 8): 1, (3, 2, 9): 1, (3, 2, 10): 1, (3, 2, 11): 1, (3, 2, 12): 1, (3, 2, 13): 1, (3, 2, 14): 1, (3, 2, 15): 1}

[ichabod801]

You are always getting the maximum value for f_set because for each pair of initial values, you are going through every value in f_set (line 7). You only want to get one value in f_set per pair of initial values.

1 2 3 4 5 6 7 8 9 10 11

N=[1,2,3] t={} f_set=[5,2,1,10,15,1,3,1] f_index = 0 for x in N:     for y in N:         if x is not y:             for f_no in range(1,f_set[f_index]+1):                 t[x,y,f_no]=1             f_index += 1 print(t)

[pmt]

Thank you very much for your help. It worked and I could get the result as I want.

[DeaD_EyE]

With product from itertools you can remove the nested for-loop for x and y.

1 2 3 4 5 6 7 8 9 10 11 12 13

from itertools import product     N = [1, 2, 3] t = {} f_set = [5,2,1,10,15,1,3,1] f_index = 0 for x,y in product(N, N):     if x is not y:         for f_no in range(1, f_set[f_index] + 1):             t[x, y, f_no] = 1         f_index += 1 print(t)

With a card deck it's easier to understand:

1 2 3 4 5 6 7 8 9

from itertools import product from itertools import chain   # 2 - 10, Jack, Queen, King, Ace numbers = chain(range(2,11), ['Jack', 'Queen', 'King', 'Ace']) colors = ['♠', '♡', '♣', '♢']   for color, number in product(colors, numbers):     print(f'{color} {number}')

The Result

Output:
♠ 2
♠ 3
♠ 4
♠ 5
♠ 6
♠ 7
♠ 8
♠ 9
♠ 10
♠ Jack
♠ Queen
♠ King
♠ Ace
♡ 2
♡ 3
♡ 4
♡ 5
♡ 6
♡ 7
♡ 8
♡ 9
♡ 10
♡ Jack
♡ Queen
♡ King
♡ Ace
♣ 2
♣ 3
♣ 4
♣ 5
♣ 6
♣ 7
♣ 8
♣ 9
♣ 10
♣ Jack
♣ Queen
♣ King
♣ Ace
♢ 2
♢ 3
♢ 4
♢ 5
♢ 6
♢ 7
♢ 8
♢ 9
♢ 10
♢ Jack
♢ Queen
♢ King
♢ Ace

[pmt]

@DeaD_EyE ..Thanks for your suggestion.