##### Proper use of if..elif..else statement
 Proper use of if..elif..else statement nick1941 Unladen Swallow Posts: 2 Threads: 1 Joined: Mar 2020 Reputation: Mar-05-2020, 11:40 PM (This post was last modified: Mar-05-2020, 11:56 PM by scidam.) I'm a retired software engineer who has programmed in a large number of different languages, but I am new to Python. As my first effort at writing a Python script, I started working on a program to computer Fibonacci numbers. My initial code is shown below. ```def Fibonacci(): number = 3 f1 = 1 f2 = 1 if number == 1: print (f1) elif number = 2: print (f2) else: n = 3 while n <= number: f3 = f1 + f2 f1 = f2 f2 = f3 print (f3) n = n + 1```However, I am getting a syntax error at the beginning of the "elif" line. Looking in the Python Language Reference showed by the syntax, but there were no examples I could find of actually using this structure. Could you please tell how to rework that elif statement so I do not get a syntax error? Thanks! BTW, the code I pasted in was properly indented (I think), but I notice when viewed in the forum, it's all squished to the left. Reply Posts: 818 Threads: 1 Joined: Mar 2018 Reputation: Mar-06-2020, 12:49 AM Essentially, this is an identation error. If/elif/else statements in Python have the following syntax: ```if statement1: ... some code elif statement2: .... some code else: .... some code```So, you need to fix identations in your code, e.g. ```def Fibonacci(): number = 3 f1 = 1 f2 = 1 if number == 1: print (f1) elif number == 2: # (NOTE: = is an assignment operator; == is used for comparison) print (f2) else: n = 3 while n <= number: f3 = f1 + f2 f1 = f2 f2 = f3 print (f3) n = n + 1``` Reply nick1941 Unladen Swallow Posts: 2 Threads: 1 Joined: Mar 2020 Reputation: Mar-06-2020, 11:22 PM Thanks for the help. The "number = 2" was really a typo. I know it should have been "==". Reply

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