Remove from end of string up to and including some character

[lbtdne]

Hi all,

I'm trying to take some string, stri_ , and iterate through it until I find a particular character. Then, I will update the stri_ to be stri_ with that character and everything after it removed.

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#  Working with url_ , a string of any length url_ = url_[:url_.find(".")]   #  For url_ == "wikipedia.com", url_ should become "wikipedia". print(url_)  # wikipedia

The above works fine in most cases, however I ran into problems with the below.

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#  Working with url_ , a string of any length url_ = url_[:url_.find(".")]   #  For url_ == "en.wikipedia.com", url_ should become "en.wikipedia". print(url_)  # en

Is there any way I can do something similar to rstrip(), but instead of removing a single character, remove every character rstrip() checked before it found "." ie. the last "." in the string?

Thanks,

K

[DreamingInsanity]

You were on the right lines with rstrip. Instead use rsplit(), which takes two arguments. A delimiter and a maxsplit.

1	result = url_.rsplit('.', 1)[0]

It doesn't matter how many '.' you have at the front of the string, it will only every remove anything after the last '.':

Output:
>> a = "wikipedia.com"
>> print(a.rsplit(".", 1)[0])
>> wikipedia
>> a = "en.wkikipedia.com"
>> print(a.rsplit(".", 1)[0])
>> en.wkikipedia
>> a = "en.something.somethingelse.wikipedia.com"
>> print(a.rsplit(".", 1)[0])
>> en.something.somethingelse.wikipedia

[menator01]

change url_find('.') to url_rfind('.') will give you what you want

Output:
>>> url = 'wikipedia.com'
>>> print(url[:url.rfind('.')])
wikipedia
>>> url = 'en.wikipedia.com'
>>> print(url[:url.rfind('.')])
en.wikipedia