How to reduce the following code to run in sequence?

[Giggel]

Hello all,
I would like to reduce the following python code.
I have one list:

1	a=[one, two, three, four]

And the following statement s are all true

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if a[0] in b:      print(a[1]) if a[1] in b:      print(a[2]) if a[2] in b:      print(a[3]) if a[3] in b:      print(a[0])

How can I reduce this to two lines of code and still to run in sequence? It will permit list a to be of "n" length and I will not have to add them individually.

[menator01]

It would help to know what b is.

[Giggel]

1	b=["five","four","three","two","one"]

I've said is true.

[menator01]

Here is a couple of examples

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a = ['one','two','three','four'] b = ['one','two','three'] # First for i in range(len(a)):     if a[i] in b:         print(f'{a[i]} is in b')     else:         print(f'{a[i]} in not in b')   #Second [print(a[i]) for i in range(len(a)) if a[i] in b]

Output:
1st example
one is in b
two is in b
three is in b
four in not in b

2nd example
one
two
three

[Giggel]

Thank you!