Why do these codes give different answers?

[pooyan89]

My goal is to write a function that takes a letter as an argument, it loops through its words and gives me False if it contains 'e' otherwise it is True.
The correct code is:

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def has_no_e(letter):     for i in letter:         if i=='e':             return False               return True

But I tried with one another attempt:

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def has_no_e2(letter):     for i in letter:         if i!='e':             return True               return False

But this code does not give me the correct answer if I try for example

1	print(has_no_e2('Robert'))

What is wrong?!

[DeaD_EyE]

1 2	for char in "Robert":     print(char)

Output:
R
o
b
e
r
t

The first element is the str R. What do you think will happen, if you return True?

[pooyan89]

1 2	for char in "Robert":     print(char)

Output:
R
o
b
e
r
t

I thought it would loop through all the words in there.
The first element is the str R. What do you think will happen, if you return True?

[pooyan89]

1 2	for char in "Robert":     print(char)

Output:
R
o
b
e
r
t

The first element is the str R. What do you think will happen, if you return True?

f
Allright ! I've got it now! I missunderstood the Boolean! True or False will terminate the whole loop

[buran]

True or False will terminate the whole loo

No, not the True or False, but the return statement.

[DeaD_EyE]

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def function():     for _ in range(10):         return # <-- function will return None                # the loop does not continue if you return from a function                # in this case the first iteration will return None                # the None is implicit

It's not the True or False, the return statement is what will return something.

A plain return returns None.
A return in a for-loop will imminently return and the for-loop won't do further iterations.