concatenat - shutil

[jmabrito]

import shutil
t1 = 'bjjj'
t2 = 4455
t3 = '.txt'
t6 = print(t1+str(t2)+t3)
shutil.copy('bjjj.txt', 't6')
shutil.copy('bjjj.txt', 'bjjj4455.txt')

NOTE NOTE
I have a job file called bjjj.txt. When the program ended, I wanted it to be copied to the same name concatenated with a variable. I made immense attempts to no avail. If you put fixed bjjj4455.txt it works perfectly. But I want to increase the number 4455 +1 ...
Thank you

buran write Feb-11-2021, 11:57 AM:
Please, use proper tags when post code, traceback, output, etc. You have been advised to do so.
See BBcode help for more info.

[BashBedlam]

Is this what your are looking for?

prefix = 'bjjj'
version_number = 4455
version_number += 1
sufix = '.txt'
new_file_name = f'{prefix}{version_number}{sufix}'
shutil.copy('bjjj.txt', new_file_name)

or condensed:

new_file_name = f'bjjj{version_number}.txt'

[jmabrito]

thank you. what should I do to complete this request of mine. Worked perfectly. thanks again

[jmabrito]

Is this what your are looking for?

prefix = 'bjjj'
version_number = 4455
version_number += 1
sufix = '.txt'
new_file_name = f'{prefix}{version_number}{sufix}'
shutil.copy('bjjj.txt', new_file_name)

or condensed:

new_file_name = f'bjjj{version_number}.txt'

NOTE NOITE

100% sorted out

I have a problem to finalize the program for the post subject "goto". there is a line in the "for _ in range (1)" cycle that says
"print (f '{k} EXISTS')" must go back to for _, as this number that exists should not be announced. please, can you help me?! In the hands of a good programmer, it should be easy. Do you have access to my GOTO order?