<class 'str'> ?

[pprod]

Why is that '\d' in a regular expression finds digits but then if those digits are stored in a variable, print(type(variable)) returns <class 'str'>?

1 2 3 4 5 6 7 8 9 10 11 12

import re   string = ''' 10.00 22.34 31.23 '''   test_re = re.compile(r'\d') test = test_re.findall(string) print(test)   for i in test:  print(type(i))

Output:
['1', '0', '0', '0', '2', '2', '3', '4', '3', '1', '2', '3']
<class 'str'>
<class 'str'>
<class 'str'>
<class 'str'>
<class 'str'>
<class 'str'>
<class 'str'>
<class 'str'>
<class 'str'>
<class 'str'>
<class 'str'>
<class 'str'>

[buran]

regular expressions are all about strings. It's a char that is a digit, it is not expected to cast the result to numeric type. It's also evident from the list that you print - it's a list of str, not int

[deanhystad]

Because digits are strings. Did you think it was converting the string to an int?