Try,Except,Else to check that user has entered either y or n (Code block pasted)

[RandomNameGenerator]

Hey up, pretty simple query. I just want to check the user has entered either y or n , its going straight to the else: regardless of the input
Thanks for anybody who has a moment to give feedback.

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def ask():     while True:         try:             reply = str(input("Do you want another drink Y/N "))         except:             while reply.lower() not in ("y","n"):                 print("you have incorrectly entered - pick Y/N")                 continue         else:             print('you have correctly entered y or n')             break ask()

[Yoriz]

input returns a string so there is no need to convert the returned string into a string.
There is nothing to trigger an exception so the except part of your code doesn't happen.
As there is no conversion from the input that is likely to raise an exception you could simply use the following

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def ask():     while True:         reply = input("Do you want another drink Y/N ").lower()         if reply not in ('y', 'n'):             print("you have incorrectly entered - pick Y/N")         else:             print(f'you have correctly entered {reply}')             break     return reply     ask()

There is a forum post that you might find helpful
Validating User Input

[buran]

there is no error raised on this line reply = str(input("Do you want another drink Y/N ")), so except block is never executed and it jumps to else block. And input() returns str so there is no need to explicitly convert it with str(input("Do you want another drink Y/N "))

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def ask():     while True:         reply = input("Do you want another drink Y/N ")         if reply.lower() in ("y", "n"):             print('you have correctly entered y or n')             break         else:             print("you have incorrectly entered - pick Y/N")   ask()

[RandomNameGenerator]

Thanks Buran and Yoriz for your assistance.