Regex find string then return 10 character after it

[pyStund]

Hi,
I’ve been looking at Regex and regex cheat sheets and can find how to search for a string and then group them but it would be useful for me to be able to set a number of variables.

For example

varX = “x: “
varY = “y: “
varZ = “z: “

And then to specify for regex Python that I want to return the next 10 following characters.

Can someone point me to the terms to search for syntax in manuals to read

Thanks for your help

[rob101]

You may be over complicating this (or maybe I'm over simplifying it) because you could achieve the objective with a simple sting slice:

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text_string = "For some reason x:is in this string"   varX = "x:"   index = text_string.find(varX)+len(varX)   print(text_string[index:index+10])

[deanhystad]

You question is unclear. Forget about regex and Python and describe your problem. Something like:

This is an example of some text I want to parse (provide example). I want my program to find strings that look like this (provide example) and I want to do this with the matching string(describe processing performed on string).

I have no idea what you mean by "group them" or "useful for me to be able to set a number of variables".

[pyStund]

Rob101 understood it and got the answer right.
Thanks for your help though.
The personalities of commenters you find in the forums with replies like this match the Arduino forums.
Im not sure if it is a game to send something back to lift message counts, or if its like men who need to drive big cars to compensate for lacking authority in other areas of their lives.

You question is unclear. Forget about regex and Python and describe your problem. Something like:

This is an example of some text I want to parse (provide example). I want my program to find strings that look like this (provide example) and I want to do this with the matching string(describe processing performed on string).

I have no idea what you mean by "group them" or "useful for me to be able to set a number of variables".

[pyStund]

Brilliant, thanks @rob101 good work, nice guy

You may be over complicating this (or maybe I'm over simplifying it) because you could achieve the objective with a simple sting slice:

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text_string = "For some reason x:is in this string"   varX = "x:"   index = text_string.find(varX)+len(varX)   print(text_string[index:index+10])

[deanhystad]

Honest, I did not get what you were trying to say (still don't really). Are you trying to parse text that contains patterns like this?

"This is my pattern x:0123456789 and I want to get the 0123456789"

If that is the case, what if the text contains something like this?

"This has an x:0123 but there is a blank. Do I just take the next 10 characters or do I stop at the blank, or is this not a match?"
"This does not have enough characters after the pattern. Should it match x:1234"
"These patterns overlap. Should they count? x:123 y:4657"

And I really don't get what do you mean by "group them"? Do you want a regex that looks for "x:", "y:" or "z:"? You could do that with [xyz]:\w{10}

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import re   text = "this is x:0123,  some things y:0123456, that may or may not z:0123456789, match the pattern x:abcdefghijk, y:123 z:4567" pattern = re.compile("[xyz]:\w{10}")   print(re.findall(pattern, text))

Output:
['z:0123456789', 'x:abcdefghij']

This grabs the two strings that start with x:, y: or z: and are followed by 10 non-whitespace characters.

If changed to just grab the next 10 characters, it does this:

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import re   text = "this is x:0123,  some things y:0123456, that may or may not z:0123456789, match the pattern x:abcdefghijk, y:123 z:4567" pattern = re.compile("[xyz]:.{10}")   print(re.findall(pattern, text))

Output:
['x:0123,  som', 'y:0123456, t', 'z:0123456789', 'x:abcdefghij']

Now I get all the x:, y: and z:'s that are followed by 10 characters and don't overlap with another pattern.
['x:0123, som', 'y:0123456, t', 'z:0123456789', 'x:abcdefghij', 'y:123 z:4567']
Note that z:4567 at the end does not count as a match because z: is not followed by 10 characters.

And what did you mean by this?

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varX = “x: “ varY = “y: “ varZ = “z: “

Is varY supposed to be a variable referencing the "y:" pattern, or is it a variable used to reference the 10 characters following "y:" in the text you are searching?

If your posts on the Arduino forum are this vague I understand why you get more questions than answers. Remember, you have all the details and we know nothing except the info in your post. Write posts as though the audience has no idea what you are talking about, because that is True. My favorite format is "Here is my input, this is my expected output, additional information." Then I can test my reply against the input and output to see if I'm answering the question correctly. If you can't do that, provide lots of details. Details are important, especially with something like regular expressions where two patterns that look almost the same will give radically different results.

[Pedroski55]

You can get the start and end positions of any pattern with re

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pattern = re.compile('x:') # this returns a tuple with the position of the pattern in your string start_stop = pattern.search(astring).span()

You could do it like this:

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import re astring = 'aaaax:bbbbbbbbbbbbbbby:cccccccccccccccccccz:ddddddddddddddddd' myvars = ['x:', 'y:', 'z:', 'dog'] length = 10 results = [] for item in myvars:     pattern = re.compile(item)     # find where the search string starts     start = pattern.search(astring)     # if the pattern is not found search returns None     if not start == None:         #get the span tuple         tup = start.span()         # change the tuple to get what you want         newtup = (tup[0] + 2, tup[1] + length)         # slice the string         wanted = astring[newtup[0]:newtup[1]]         results.append(wanted)