questions about dict.get

[akbarza]

hi
in the below code:

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#dict_get.py print(help(dict.get)) ''' Help on method_descriptor:   get(self, key, default=None, /)     Return the value for key if key is in the dictionary, else default. ''' dict_1={'ali':12,"mohammad":15,"fatemeh":20} dict_1.get('ali') #12 dict_1.get('fatemeh') #20 dict_1.get('fatemeh',default='40')       #line 14 # Traceback (most recent call last): #   File "<stdin>", line 1, in <module> # TypeError: dict.get() takes no keyword arguments dict_1.get('fatemeh','40') 20 dict_1.get('fatemeh440','40') '40'

in help(dict.get), what are the meanings of self and / ?
in line 14, I want to use dict.get as in help(dict.get), but I am taken with an error(error message is commented in the above code) What is the problem?
in line 15, I omitted the default= from line 14, and I don't have the error message.
thanks for any guidance

[Larz60+]

to get the value of a dictionary entry use dictname['key']
like:

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>>> dict_1={'ali':12,"mohammad":15,"fatemeh":20} >>> x = dict_1['fatemeh'] >>> x 20

or just:

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>>> dict_1={'ali':12,"mohammad":15,"fatemeh":20} >>> print(dict_1['ali']) 12 >>>

[deanhystad]

self is the first argument to any instance method. It is the instance that called the method. In your example:

1	dict_1.get('ali')

"self" in get() would be dict_1.

/ in the argument list indicates that all arguments left of the / are position only arguments. This is why you got an error when trying to use the keyword "default". * is a similar delimiter. All arguments right of * are keyword only arguments. You can read about them here:

https://realpython.com/python-asterisk-a...arameters/