removing one list element without using its index

[DeaD_EyE]

Your code example is wrong.

• Indentation of return
  
• the use of range(len(element)), iterate directly
  
• alist is modified in-place and is also returned
  
• Iterating over a list and modifying the list in-place will throw an IndexError.
  

If you change then indentation to iterate over all elements, then you would get an IndexError.

This modifies the list in-place and does return None:

def remove_it(val, alist):
    remove = []

    for index, element in enumerate(alist):
        if element == val:
            remove.append(index)
    
    for index in reversed(remove):
        alist.pop(index)


my_list = [3, 1, 2, 3, 4, 5, 3]

print(my_list)
remove_it(3, my_list)
print(my_list)