[difflib] read files with SequenceMatcher

[JamieVanCadsand]

Hey Python Programmers...

I try to write an script to read files with difflib writting an script like this:

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import difflib   file1 = open("File1.txt", "r") file2 = open("File2.txt", "r") result = difflib.SequenceMatcher(None, file1.read(), file2.read())   print(result)

If i run my script, i get an error. This script don't work. I don't
know what the error is, but simply said... this script don't work.

What is wrong with my script. I write this script only to learn handle
with these functions or reather... i am in the learn fase of python.
Its only to learn use the difflib functions for training.

I do this to train my self in python programming.

Can anyone help me with my script, but whats wrong with this...
Thanks for helping, Jamie van Cadsand.

[wavic]

difflib.SequenceMatcher returns a difflib.SequenceMatcher object. You can't just print it. Instead, see which methods of this object are useful for your needs.

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In [4]: m = difflib.SequenceMatcher(None, s1, s2)   In [5]: type(m) Out[5]: difflib.SequenceMatcher

See the docs

[buran]

what you get is not an error, but you just print the representation of
SequenceMatcher object, e.g. something like

Output:
<difflib.SequenceMatcher instance at 0x030917B0>

you need to use some of the SequenceMatcher methods to get meaningful result, e.g.
if file1.txt is

Output:
abcd

and file2.txt is

Output:
bla
abcd

then

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import difflib   with open("file1.txt", "r") as f1, open("file2.txt", "r") as f2:     result = difflib.SequenceMatcher(None, f1.read(), f2.read())   print(result.get_matching_blocks())

will get you this:

Output:
[Match(a=0, b=4, size=4), Match(a=4, b=8, size=0)]

still not very human, so you may want to use some of the other classes that build on top of differ.SequenceMatcher, e.g. difflib.Differ

working with the same txt files:

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import difflib   with open("file1.txt", "r") as f1, open("file2.txt", "r") as f2:     dif = difflib.Differ()     print('\n'.join(dif.compare(f1.read(), f2.read())))

Output:
+ b
+ l
+ a
+

a
b
c
d

[JamieVanCadsand]

what you get is not an error, but you just print the representation of
SequenceMatcher object, e.g. something like

Output:
<difflib.SequenceMatcher instance at 0x030917B0>

you need to use some of the SequenceMatcher methods to get meaningful result, e.g.
if file1.txt is

Output:
abcd

and file2.txt is

Output:
bla
abcd

then

1 2 3 4 5 6

import difflib   with open("file1.txt", "r") as f1, open("file2.txt", "r") as f2:     result = difflib.SequenceMatcher(None, f1.read(), f2.read())   print(result.get_matching_blocks())

will get you this:

Output:
[Match(a=0, b=4, size=4), Match(a=4, b=8, size=0)]

still not very human, so you may want to use some of the other classes that build on top of differ.SequenceMatcher, e.g. difflib.Differ

working with the same txt files:

1 2 3 4 5

import difflib   with open("file1.txt", "r") as f1, open("file2.txt", "r") as f2:     dif = difflib.Differ()     print('\n'.join(dif.compare(f1.read(), f2.read())))

Output:
+ b
+ l
+ a
+

a
b
c
d

OK, Thanks for you help with my code... maby i try your way tomorrow and thad expirimenting
with difflib at the hope thad it works. I hope thad this get succes, but now i don't can try
your code, i am working at the GlazenPui, just maby i can even tonight or tomorrow try your
code. Now i am working...

Jamie.