broken if statement????

[DarthTader]

ok so this sample code is intended to run (at this time) infinetly until i re-run the code (f5)

my current problem is after i call the button function. i am attempting the first part of what will be an if elsif else statement to choose Longsound, Shortsound, or Medsound based on input. (the input will eventually be one of three buttons in a glove instead of 1, 2, or 3 on a keyboard, and eventually the random number will be transferred to the sound functions to pick one of 13 sound files(i was thinking something similar to a switch statement in C++) in each function.)
for now the if statement just to test to see if i can print long sound to the screen is not working
this will eventually be run on a raspberry pi.............. :(

it runs otherwise with no errors.

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import random press = 0 def button():        press=input("enter\n")     print('pressed ', press)     return press      def RNG():#defnine random number generator     x=0     rnv = random.randint(1,13)     print('Rnv is ',rnv)     return rnv   def Longsound(): #plays a long sound     RNG()#calls random number generator     print("longsound")     print(RNG())     x=RNG()     print("l",x,".wav")   def Shortsound():#plays short sound     RNG()     print("shortsound")   def Medsound():     RNG()     print("mediumsound")           def main():     print("\n\nhello world\n")     press = button()     print("main post button",press)     if press == 1:#attempting to call (print the name) a function         print("longsound") ''' main program run ''' while True:   #loops program ill figure out how to exit and shutdown later     main() #calls main program     #if press == 1:#attempting to call (print the name) a function         #print("longsound")

[Mekire]

input returns a string.  "1" is not equal to 1.  Either convert one to a string or the other to an int before the comparison.

[DarthTader]

Wow duh

Thanks. Why is it the simple things we over look