If/else problems

[Terafy]

Yes you could go with
.upper()
.lower()
and the best one to suit your need is:
.capitalize()

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print('WiZaRd'.lower()) print('WiZaRd'.upper()) print('WiZaRd'.captialize())

Output:
wizard
WIZARD
Wizard

[Skelbo]

Hmm where am I supposed to put it? in the input line? input.capitalise?

[Terafy]

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def c():     found = False     jobs = input("Enter the job title: ")     #right here!     jobs = jobs.capitalize()     for b in employees:         if jobs == b[2]:                            ## what with the len(i) in these if-statement             if len(b)==5:                 print('%-30s' % (b[4]+ ','+' '+b[3]))                 found = True             if len(b)==6:                 print('%-30s' % (b[5]+','+' '+b[3]+' '+b[4]))                 found = True             if len(b)==7:                 print('%-30s' % (b[6]+','+' '+b[3]+' '+b[4]+' '+b[5]))                 found = True     if found == False:         print("There is no such job")

[squenson]

To put all the chances on your side, you should write:

1	if jobs == b[2].capitalize():

Just in case that the input file contains job names written in lower cases or upper cases.

[Skelbo]

Yay thanks! Fully working exercise now. Satisfying.

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I see. What could go wrong with jobs = jobs.capitalize()?

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Oooh got it.

[squenson]

In fact, you need both:
First jobs = jobs.capitalize()
Second, when you do the comparison, make sure that you compare with something that is capitalized as well, hence if jobs == b[2].capitalize():

[Skelbo]

You guys willing to help with second part of the assignment?

[Terafy]

Yes, it a good standard practice. But the data he provided didn't have that problem so it wasn't necessary to do so.

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Yes, I on board! Kind of annoyed that we did not manage to get the previous one in on time...

[Skelbo]

I made a new thread for the second part. I think that's best. It's called word search grid.