Product of maximum in first array and minimum in second

[Thethispointer]

So I am practicing the following

Given two arrays of size N1 and N2 respectively, the task is to calculate the product of max element of first array and min element of second array.

https://practice.geeksforgeeks.org/probl...n-second/0

I was writing this program and got hung up on an error...

Traceback (most recent call last):
File "C:\Users\groundZero Admin\Documents\Python\arrayPracetice1.py", line 22, in <module>
y = A[i]
IndexError: list index out of range

#Given two arrays of size N1 and N2 respectively, the task is to 
#calculate the product of max element of first array and min
#element of second array.
#
#

A = [1, 50, 2, 7, 3, 8]
B = [1, 50, 2, 7, 3, 8, 75, 77, 0]

listALength = len(A)
listBLength = len(B)

#These print functions were used to test the len function on arrays during
#this study session. They're now commented out to make them inactive.
#print(listALength)
#print(listBLength)

#Take the length of the array - 1 to increment the list via a loop

x = A[0]
for i in A:
    y = A[i]
    if y > x:
        x = y

print(x)

Please help me! Thank you!

[j.crater]

The "i" in your line for i in A: is not an index as you have probably expected. It is the element of A accessed in a single iteration of for loop. Try this:

for i in A:
    print(i)

For getting indexes you can use enumerate. Here is an example:

my_list = ['one', 'two', 'three']
for i, number in enumerate(my_list):
    print(i, number)

As a side note, you may want to get yourself familiar with min() and max() Python functions.
Also, array in Python is called list, if you care about avoiding "foul language" ;P

[Thethispointer]

Awesome, awesome, awesome! Thank you!

---

Here is the functional code, now let's add min() and max()... or maybe tomorrow morning as it's getting pretty late here in the Midwest.

#Given two Lists of size N1 and N2 respectively, the task is to 
#calculate the product of max element of first List and min
#element of second List.

A = [1, 50, 2, 7, 3, 8]
B = [1, 50, 2, 7, 3, 8, 75, 77, 0]

listALength = len(A)
listBLength = len(B)

x = A[0]
for i, number in enumerate(A):
    y = A[i]
    if y > x:
        x = y

print(x)

---

Okay, with min() and max().

#Given two Lists of size N1 and N2 respectively, the task is to 
#calculate the product of max element of first List and min
#element of second List.
A = [1, 50, 2, 7, 3, 8]
B = [1, 50, 2, 7, 3, 8, 75, 77, 0]
print(min(B) + max(A))

[j.crater]

Code looks much nicer/shorter. Except the task ultimately requires a product, not sum of those elements, if I understood right =)

[Thethispointer]

Code looks much nicer/shorter. Except the task ultimately requires a product, not sum of those elements, if I understood right =)

Yes indeed you are correct! I guess I should read more carefully! Thank you again for your help, I will definitely post some more code onto the forum when I find another issue I am hung up on!

[j.crater]

No problem, we are glad to help! =)
Beside posting when you hit an obstacle, feel free to also post in Completed Scripts/Snippets subforum, if you would like to share your working code and get some feedback for improvement ;)

[Larz60+]

Given two arrays of size N1 and N2 respectively, the task is to calculate the product of max element of first array and min element of second array.

>>> A = [1, 50, 2, 7, 3, 8]
>>> B = [1, 50, 2, 7, 3, 8, 75, 77, 0]
>>> max(A) * min(B)
0
>>>

[j.crater]

I guess that is alright. Example on the link Thethispointer provided even has a negative number in B list. So result can end up negative as well.

[Larz60+]

>>> B = [1, 50, 2, 7, 3, 8, 75, 77, 0, -5]
>>> max(A) * min(B)
-250
>>>

[Thethispointer]

No problem, we are glad to help! =)
Beside posting when you hit an obstacle, feel free to also post in Completed Scripts/Snippets subforum, if you would like to share your working code and get some feedback for improvement ;)

Yeah, I will do this!

Given two arrays of size N1 and N2 respectively, the task is to calculate the product of max element of first array and min element of second array.

>>> A = [1, 50, 2, 7, 3, 8]
>>> B = [1, 50, 2, 7, 3, 8, 75, 77, 0]
>>> max(A) * min(B)
0
>>>

Thank you! This is accurate