Fizz Buzz Example

[Kai.]

Just a simple Fizz Buzz example answer that you guys can dissect and point things out.   

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count = 0   while count <= 100:            if ((count % 5) == 0 and (count % 3) == 0):      print "FizzBuzz"      count = count + 1        elif (count % 3) == 0:         print "Fizz"         count = count + 1            elif (count % 5) == 0:         print "Buzz"         count = count + 1        else:         print count         count = count + 1

[Mekire]

By using a for loop you remove the need for the count number. In fact, if this actually were for a job interview, whether or not an applicant used a while or a for would be quite telling of Python knowledge. Also there is no need to have a conditional for both parts being true.

A sane version of fizz buzz could look like this:

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for i in range(1,101):     line = ""     if i%3 == 0:         line = "Fizz"     if i%5 == 0:         line += "Buzz"     print(line or i)

That said, I quite like sillier versions like this:

1 2	for i in range(1,101):     print("Fizz" * (i%3==0) + "Buzz" * (i%5==0) or i)

There is also a slightly shorter version than that but it isn't as clear.
Rosetta Code is a fun site if you don't know about it:
https://www.rosettacode.org/wiki/FizzBuzz#Python

[Kai.]

Wow @Mekire that is way above my pay grade, I will study this, thank you for the feedback!

[nilamo]

In fact, if this actually were for a job interview, whether or not an applicant used a while or a for would be quite telling of Python knowledge.

Almost any programming experience, for that matter.  I actually can't think of a language where you'd need to use a while loop for this.  Even php has for loop syntax for this sort of thing:

1	for ($i=0; $i < 101; $i++) {  /* fizzbuzz math */ }

[Skaperen]

In fact, if this actually were for a job interview, whether or not an applicant used a while or a for would be quite telling of Python knowledge.

Almost any programming experience, for that matter.  I actually can't think of a language where you'd need to use a while loop for this.  Even php has for loop syntax for this sort of thing:

1	for ($i=0; $i < 101; $i++) {  /* fizzbuzz math */ }

try it in assembly

[DDD]

By using a for loop you remove the need for the count number.  In fact, if this actually were for a job interview, whether or not an applicant used a while or a for would be quite telling of Python knowledge.  Also there is no need to have a conditional for both parts being true.

A sane version of fizz buzz could look like this:

1 2 3 4 5 6 7

for i in range(1,101):     line = ""     if i%3 == 0:         line = "Fizz"     if i%5 == 0:         line += "Buzz"     print(line or i)

That said, I quite like sillier versions like this:  

1 2	for i in range(1,101):     print("Fizz" * (i%3==0) + "Buzz" * (i%5==0) or i)

There is also a slightly shorter version than that but it isn't as clear.
Rosetta Code is a fun site if you don't know about it:  
https://www.rosettacode.org/wiki/FizzBuzz#Python

Gotta love rosetta lol.