IndexError: tuple index out of range

[Truman]

tp=(1,2,3,4,5,6,7,8,9,10)
for i in tp:
    lt = []
    if tp[i]%2 == 0:
        lt.append(tp[i])
    else:
	    pass
tp2 = tuple(lt)
print(tp2)

I don't understand why is i out of range.

After change in code I receive the same message

tp=(1,2,3,4,5,6,7,8,9,10)
for i in tp:
    lt = []
    for i in range(1,11):
        if tp[i]%2 == 0:
            lt.append(tp[i])
        else:
	        pass
tp2 = tuple(lt)
print(tp2)

[woooee]

What is the complete error message which shows which line the error is on? Print i right after the for i in tp, and then print tp[i], which will error, so print on a separate line. You don't want 2 statements here as the for i in tp is already accessing the values in tp. There are additional problems in the next for i in tp, but that is for you to figure out.

[wavic]

Because you are using the values from the tuple as an index to the elements in the same tuple.
tp contains 10 elements. But tp[10] is the 11th element ( indexing starts from 0 ) and of course, it doesn't exist.

Change the if statement.

if i % 2 == 0:
    lt.append(i)

In the first code snippet.

[Truman]

wavic, the output is now (10,)

---

What is the complete error message which shows which line the error is on? Print i right after the for i in tp, and then print tp[i], which will error, so print on a separate line. You don't want 2 statements here as the for i in tp is already accessing the values in tp. There are additional problems in the next for i in tp, but that is for you to figure out.

tp=(1,2,3,4,5,6,7,8,9,10)
for i in tp:
    print(i)
    print(tp[i])
    lt = []
    if i%2 == 0:
        lt.append(i)
    else:
        pass
tp2 = tuple(lt)
print(tp2)

it gives line 4

[wavic]

Again, do not use the values as an index!

How the output is (10,)? What have you tried exactly?

Here is the same code. You can skip the else statement.

>>> lt = []
>>> tp = (1, 2, 3, 4, 5, 6, 7, 8, 9, 10)
>>> for i in tp:
...     if i % 2 == 0:
...         lt.append(i)
...     else:
...         pass
... 
>>> tp2 = tuple(lt)
>>> print(tp2)
(2, 4, 6, 8, 10)

I see now that your lt = [] is inside the for loop. So on every iteration you wipe it out to an empty list

[Truman]

lt = []
tp=(1,2,3,4,5,6,7,8,9,10)
for i in tp:
    
    if i%2 == 0:
        lt.append(i)
   
tp2 = tuple(lt)
print(tp2)

Now it works and I completely understand it. Thank you.