Vowels and Consonants detector

[OmarSinno]

Objective is: to print True when it's a vowel, and False when it's a consonant, WITHOUT using if conditions.

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vowels = ['o', 'i', 'y', 'e', 'a','u'] consonants =['b, c, d, f, g, h, j, k, l, m ,n ,p, q, r, s, t, v, w, x, z']   def is_vowel(c):     for character in vowels:         print(True)     for character in consonants:         print(False)   is_vowel('banana')

Here's what I got when I executed the program:

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True True True True True True False

This is obviously false because I should get False True False True False True.
Any help?

[buran]

execute

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vowels = ['o', 'i', 'y', 'e', 'a','u'] consonants =['b, c, d, f, g, h, j, k, l, m ,n ,p, q, r, s, t, v, w, x, z']    def is_vowel(c):     for character in vowels:         print(character, True)     for character in consonants:         print(character, False)    is_vowel('banana')

this will help to see what your script ACTUALLY does

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Objective is: to print True when it's a vowel, and False when it's a consonant, WITHOUT using if conditions.

1 2 3 4 5 6 7 8 9 10

vowels = ['o', 'i', 'y', 'e', 'a','u'] consonants =['b, c, d, f, g, h, j, k, l, m ,n ,p, q, r, s, t, v, w, x, z']   def is_vowel(c): for character in vowels: print(True) for character in consonants: print(False)   is_vowel('banana')

Here's what I got when I executed the program:

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True True True True True True False

This is obviously false because I should get False True False True False True.
Any help?

[Sagar]

You are not using "c" which is passed into the function is_vowel()

[j.crater]

You have an argument "c" that you pass to the function is_vowel, but where/how do you use it?
Also, compare how you have defined vowels and consonants lists (or what they contain rather).

[OmarSinno]

Isn't c the string that is supposed to be called later on in the code?

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def is_vowel(c):     for character in c:         print(character, True)     for character in c:         print(character, False)

I adjusted it to this code, still giving me the same results.

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I have realized that when it's finding a vowel, it is printing True 6 times, which is the length of the string 'banana'. Same thing goes for when it finds a consonant.
Unlike this code:

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def is_vowel2(c):     for character in c: #The Character in the word defined by the letter "c"         if character in vowels: #If this character is in the list "vowels"             print(True) #The statement is then a vowel, which is true!         else: #If not, or if else             print(False) #The statement is false, then it is a consonant!

Fortunately, I have to do it both ways (using if conditionals and without using them) so I can actually study both. Help?

[buran]

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vowels = ['o', 'i', 'y', 'e', 'a','u'] def is_vowel2(my_word):     for character in my_word: #The Character in the word defined by the letter "c"         print (character in vowels) #If this character is in the list "vowels" print True, else will print False is_vowel('banana')

or

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vowels = ['o', 'i', 'y', 'e', 'a','u'] def is_vowel(c):     return c in vowels #If this character is in the list "vowels" print True, else will print False for character in 'banana':     print(is_vowel2(character))