if-elif-else statement not executing

[laila1a]

Hi everyone, I'm new to programming so sorry in advance if my mistake is a stupid one.
I am having trouble making my if-elif-else statement execute properly in my dice rolling simulator, it always defers to the statement for the else part, no matter the input. For example, if the user inputs 1 to play again, they will be told the input is not valid. Same thing if they input 2 in order to stop playing.
Here is my code:

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from random import randint     def diceRollingSimulator():     dice = randint(1, 6)     print(dice)     diceRollingSimulator() answer = input("Would you like to play again? (enter 1 for yes or 2 for no): ") if  answer == 1:     diceRollingSimulator() elif answer == 2:     print("Thanks for playing!") else:     print("Not a valid input!")

[buran]

input() will return str. In your if/elif conditions you compare str to int. so it's never True and else clause is executed.
You can either convert answer to int e.g. answer = int(input(...)) or alterntaively, compare answer to str, e.g. if answer == '1':

[stullis]

The input() function always returns a string. Because strings are not numbers, they cannot be compared. To fix this, you need to cast the input to a number type:

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from random import randint       def diceRollingSimulator():     dice = randint(1, 6)     print(dice)       diceRollingSimulator() answer = int(input("Would you like to play again? (enter 1 for yes or 2 for no): ")) if  answer == 1:     diceRollingSimulator() elif answer == 2:     print("Thanks for playing!") else:     print("Not a valid input!")

[laila1a]

Thank you!

[buran]

1	answer = int(input("Would you like to play again? (enter 1 for yes or 2 for no): "))

Note that it will raise an exception if input is not valid for conversion to int with base 10.