count item in list

[korenron]

Hello,
how can I count part of items in list?

to be clear :
I have a list that build in this form
Final_List= [['10.0.0.1:Success', '10.0.0.2:Success', '10.0.0.3:Error', '10.0.0.4:Offline' , '10.0.0.5:Error']]

I want to know how much Succes\error\offline there is in the list (i don't mind the IP - just the total number)
I have try to run

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ok = 0 error = 0 offline = 0 for item in IP_List:     if 'Success' in item:         ok +=1     if 'Error' in item:         error +=1     if 'offline' in item:         offline += 1

maybe I used list.appand wrong?

1	Final_List.append(p.map(GetUplaudFies, Device_List))

GetUplaudFies return this

1	return ip + ":" + Upload_Status

[deanhystad]

Use a counting dictionary.

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import collections   items = ['A', 'B', 'A', 'B', 'C', 'A', 'A'] counter = collections.Counter(items) for item, count in counter.items():     print(item, count)

Output:
A 4
B 2
C 1

[korenron]

I saw this
but will it work ?
beacuse every item in the list is number:state
and I'm only want to count the state .

for my list will it not give me 200 results? I have 200 differents IP inside

[deanhystad]

p.map is giving you a list, so there is no reason to append unless you want Final_List to be a list of lists. Your code fails because FinalList[0] is ['10.0.0.1:Success', '10.0.0.2:Success', '10.0.0.3:Error', '10.0.0.4:Offline' , '10.0.0.5:Error'], not '10.0.0.1:Success' as you are expecting. Change the code to something like this:

1	Final_List = p.map(GetUplaudFies, Device_List)

You can use a counter dictionary. But maybe it isn't right for this application since there are only 3 possible outcomes and they are all known. Your code should work with the above change. But this is a way to do it with a Counter

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outcomes = [outcome.split(':')[1] for outcome in Final_List] outcomes = collections.Counter(outcomes) for item, count in counter.items():     print(item, count)

[korenron]

i guees this was my mistake
the appand after the map
I didn't realize it create my a list

well - everyday you learn somehting :-)

thank you !

[DeaD_EyE]

The Counter from collections is helpful.

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from collections import Counter     def my_filter(iterable):     """     Generator returns the state: 'Success', 'Error', 'Offline'     """     for element in iterable:         try:             ip, kind = element.split(":", maxsplit=1)         except ValueError:             continue           yield kind     def get_results(chunks):     """     Yield all chunks as Counter object     """     for chunk in chunks:         yield Counter(my_filter(chunk))     def sum_results(chunks):     """     Sum all chunks together and return one Counter object     """     final = Counter()     for result in get_results(chunks):         final += result       return final       input_data = [     [         '10.0.0.1:Success',         '10.0.0.2:Success',         '10.0.0.3:Error',         '10.0.0.4:Offline',         '10.0.0.5:Error',     ] ]     results1 = sum_results(input_data) results2 = sum_results(input_data * 10)     print(results1) print(results2)

Output:
Counter({'Success': 2, 'Error': 2, 'Offline': 1})
Counter({'Success': 20, 'Error': 20, 'Offline': 10})

If input_data is a flat list, get_results(input_data) does not require the for-loop and just return one Counter object.

FlatList-Example:

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from collections import Counter     def my_filter(iterable):     """     Generator returns the state: 'Success', 'Error', 'Offline'     """     for element in iterable:         try:             ip, kind = element.split(":", maxsplit=1)         except ValueError:             continue           yield kind     input_data = [     '10.0.0.1:Success',     '10.0.0.2:Success',     '10.0.0.3:Error',     '10.0.0.4:Offline',     '10.0.0.5:Error', ]     result1 = Counter(my_filter(input_data)) result2 = Counter(my_filter(input_data * 10)) print(result1) print(result2)

Output:
Counter({'Success': 2, 'Error': 2, 'Offline': 1})
Counter({'Success': 20, 'Error': 20, 'Offline': 10})

You should also read: https://docs.python.org/3/library/collec...ns.Counter

[korenron]

thanks
I will give it also a try

[deanhystad]

What do you think should happen when you append a list to a list? Did you think it would make the original list longer? Append (and insert) treat the argument as an object, not an iterable. From the docs:

list.append(x)
Add an item to the end of the list. Equivalent to a[len(a):] = [x].

You could use extend to add items from a list to an existing list.

Output:
list.extend(iterable)
Extend the list by appending all the items from the iterable. Equivalent to a[len(a):] = iterable

And as the extend description from the manual hints, you can do the same thing with slices. You can also concatenate lists using '+'

Lists are important in Python. You need to REALLY understand how they work or it is going to come back to bite you again and again.

[naughtyCat]

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items = ['A', 'B', 'A', 'B', 'C', 'A', 'A'] key = sorted(set(items)) for k in key:     print(k, items.count(k))

Output:
A 4
B 2
C 1